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Subtract data in Visio

Solved1.08K views5th July 2023subtract visio properties
2
Thomaz Malmberg [DevOps Advocate]264 29th May 2023 2 Comments

Hi again,

Ill try again to see if someone could help me with this because I´m totally stucke. I had already an question about this issue with lots of answers but they are not working in my case so I try again. This is the old question: https://community.dataminer.services/questions/edit/?id=107088&__nonce=bd0ea84469

An ordinary Subtract is working with just numbers but not when I´m using Param also. Is Subtract only working in format: HH:MM:SS ?

This is the example that I have tried with bad results.

// Thomaz

Marieke Goethals [SLC] [DevOps Catalyst] Selected answer as best 5th July 2023
Toon Casteele [SLC] [DevOps Enabler] commented 30th May 2023

The best way to debug these kinds of issues is always to work from the inside to the outside. Put your param placeholders separately in a shape text and check the result. Are the numbers what you expect them to be? What if you subtract the results statically? Only then can we look to combine and/or think whether this is a software issue or not. Hope that helps.

Thomaz Malmberg [DevOps Advocate] commented 30th May 2023

Hi,
I have them separated and the results from the parameter is correct.
[Param:120501/2735,6453,TL-DD-ENC] = 180
[Param:120501/2735,6454,TL-DD-ENC] = 101

Then I will subtract 6454 from 6453 and get the results and that is not working.
I have also now tried the sum that Jarno proposal and that was working.
[Sum:[Param:120501/2735,6453,TL-DD-ENC], -[Param:120501/2735,6454,TL-DD-ENC]]

So for me so is the sum working but not subtract

Thanks for your help

1 Answer

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Jarno Lernou [SLC] [DevOps Enabler]5.00K Posted 29th May 2023 4 Comments

Hi Thomaz,

Nice to meet you!

From my experience (and also from the DM Docs [Subtract:...]), I think the placeholder is only to be used with date-time and timespan. I'd let it up to the software team to either confirm or deny this statement.

I would suggest using the [Sum:X,Y,Z] placeholder. You can simply add a minus (-) sign before your param placeholder.

Example: [Sum:[param:123/45,67], -[param:123/45,89]]

Kind Regards,
Jarno

Marieke Goethals [SLC] [DevOps Catalyst] Selected answer as best 5th July 2023
Toon Casteele [SLC] [DevOps Enabler] commented 30th May 2023

Subtract should work perfectly fine with numbers FYI.

Thomaz Malmberg [DevOps Advocate] commented 30th May 2023

Hi Jarno,

Thanks for your help and the sum example you mentioned was working perfect.

Do you know how I now can get the sum of the results that I has got?
I want to have these results into a sum of all 3.
[Sum:[Param:120501/2735,6453,TL-DD-DEC], -[Param:120501/2735,6454,TL-DD-DEC]]
– (Sub)
[Sum:[Param:120501/3877,6453,TL-DD-DEC], -[Param:120501/3877,6454,TL-DD-DEC]]
– (Sub)
[Sum:[Param:120501/2742,6453,TL-DD-DEC], -[Param:120501/2742,6454,TL-DD-DEC]]
= (Sum)

Br,
Thomaz

Sebastiaan Dumoulein [SLC] [DevOps Enabler] commented 1st June 2023

This can be achieved by nesting these in a sum placeholder again:
[Sum:[Sum:[Param:120501/2735,6453,TL-DD-DEC], -[Param:120501/2735,6454,TL-DD-DEC]],[Sum:[Param:120501/3877,6453,TL-DD-DEC], -[Param:120501/3877,6454,TL-DD-DEC]], [Sum:[Param:120501/2742,6453,TL-DD-DEC], -[Param:120501/2742,6454,TL-DD-DEC]]]

Sebastiaan Dumoulein [SLC] [DevOps Enabler] commented 10th June 2023

The subtract placeholder was not yet working with numbers. Support for this has been added in 10.3.8 with RN36636. Thanks for using the community Thomaz!

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