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Show Shape based on Condition linked to Property Field from different Elements

Solved1.13K views13th July 2023
1
Daniel Lentoiu619 12th July 2022 0 Comments

Hi Dojo.

I would like to show a Shape based on two Scenarios.

#1. Based on condition(s) linked to a Property Field from One Element

I have two custom properties On_Air ( values: Off-line  / On-line ) and On_Air_Live (values: Yes / No).

I would like to show or hide the Shape based on both Property values being set up : On_Air and On_Air_Live.

I have tried to use :

[sep:-@]<A>and<B>@A|7013/2|PARAMETER:65022,On_Air|=On-line@B|7013/2|PARAMETER:65022,On_Air_Live|=Yes

Didn't work for me.

#2. Based on condition(s) linked to a Property Field from Two Elements

I would like to make things even more complicated by adding to the conditions the same Custom  Property Fields but from a different element

The Purpose is to show a connection line between two elements that are being used in a redundancy N to 1 list, to show the connection between On_Air IRD  and the BackUP IRD that is ready to take over if needed.

If I use this approach I am getting results:

Thank you.

Marieke Goethals [SLC] [DevOps Catalyst] Selected answer as best 13th July 2023

3 Answers

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1
Miguel Obregon [SLC] [DevOps Catalyst]18.56K Posted 12th July 2022 0 Comments

Hi Daniel,

Regarding the first question, can you try using the Property field:

[sep:-@]<A>and<B>@A|7013/2|Property:On_Air|=On-line@B|7013/2|Property:On_Air_Live|=Yes

More information in DataMiner Docs: Extended conditional shape manipulation actions

Miguel Obregon [SLC] [DevOps Catalyst] Edited answer 12th July 2022
You are viewing 1 out of 3 answers, click here to view all answers.
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