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Are Mediation Layer protocols intended to be directly used

Solved797 views20th July 2023mediation protocol
1
Laurens Moutton [SLC] [DevOps Enabler]8.78K 18th July 2023 0 Comments

Hi,

According to the DataMiner Mediation Layer Help, a protocol can be created to place a different view on an element, so different protocols can have the same look and feel and can generally be used by automation and correlation.

Such a protocol appears in the Protocols & Templates app between the other protocols.
-Is it the intention that an element can be created that directly uses such a mediation protocol? This is currently allowed by the UI.
-Alarm and trend templates can also be created for a mediation protocol: Is this also the intention? If so, how can such an alarm template be assigned to a real element that uses a different protocol?

Regards,

Laurens Moutton [SLC] [DevOps Enabler] Selected answer as best 20th July 2023

2 Answers

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Wouter Demuynck [SLC] [DevOps Advocate]5.93K Posted 19th July 2023 0 Comments

Hi Laurens,

Mediation layer/base protocol drivers are not intended to be used directly on a device.

Mediation drivers/parameters only exist on the highest level and are mainly used to map between there and the actual device parameters. In that sense, defining alarm or trend templates on the mediation layer makes no sense. There’s no functionality available to share a mediation alarm/trend template across different real drivers.

Ideally both of these actions should have been disallowed in the UI.

Laurens Moutton [SLC] [DevOps Enabler] Selected answer as best 20th July 2023
1
João Severino [SLC] [DevOps Catalyst]13.02K Posted 18th July 2023 0 Comments

Hi Laurens,

As far as I am aware mediation is meant to be used in conjunction with other protocols to provide a uniform look to a particular application a set of products can handle. It is not designed to be used on its own.

It is supposed to be a layer on top of something else so for that reason I believe it should not be possible to create elements directly from such a type especially since it is also not supposed to have communication defined in it (see Creating a base protocol where it mentions it is virtual protocol)

Regarding the second part of your question, I am afraid I do not have personal experience with it, so I am unable to help.

João Severino [SLC] [DevOps Catalyst] Answered question 18th July 2023
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