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Send a POST request with multipart/form-data using the tag in a protocol

Solved1.80K views11th August 2023#multipart form-data HTTP protocol session
4
MAXIMILIANO FILHO [DevOps Member]918 7th August 2023 0 Comments

Hello,

I need to send a .csv file to an API using a POST request. How can I do this using the <session> tag in the protocol? You can see below the CURL example:

curl -X POST https://[ip addrs]/api/v1/catalogs/imports?clean_catalog=1 -H "accept: application/json" -H "Content-Type: multipart/form-data" -F csv=@file.csv;type=text/csv

Thanks in advance.

MAXIMILIANO FILHO [DevOps Member] Answered question 11th August 2023

2 Answers

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Floris Cockaerts [SLC] [DevOps Advocate]2.43K Posted 8th August 2023 1 Comment

Hi Maximiliano,

This would be done by setting the Request verb to POST, configure the url and headers accordingly, and configure a Data element to point at a parameter that can be set with the content of your csv file:

Implementing HTTP communication | DataMiner Docs

As to getting the file content into the data parameter, there is the read file action (read file | DataMiner Docs) that should be executed before the session is executed, or you use a QAction if the data needs to be altered first.

MAXIMILIANO FILHO [DevOps Member] Posted new comment 11th August 2023
MAXIMILIANO FILHO [DevOps Member] commented 11th August 2023

I replied below, I can’t add code here

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